x^2=505

Solution for x^2=505 equation:

x^2=505

We move all terms to the left:

x^2-(505)=0

a = 1; b = 0; c = -505;
Δ = b2-4ac
Δ = 02-4·1·(-505)
Δ = 2020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2020}=\sqrt{4*505}=\sqrt{4}*\sqrt{505}=2\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{505}}{2*1}=\frac{0-2\sqrt{505}}{2}
=-\frac{2\sqrt{505}}{2}
=-\sqrt{505}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{505}}{2*1}=\frac{0+2\sqrt{505}}{2}
=\frac{2\sqrt{505}}{2}
=\sqrt{505}
$